Solve all the extra questions of Science Class 8 and enhance your subject knowledge. Students can download NCERT class 9 science ch 8 solutions from Vedantu for free. Therefore the car travels a total of 12 meters in the first four seconds. Therefore, the first car is displaced by 36 meters whereas the second car is displaced by 4.15 meters. Applying the Pythagoras theorem, the length of the diagonal can be obtained as follows: √(102+102)= √200= 14.14m. Extra Questions for Class 9 Science Chapter 8 Motion with Answers Solutions. MCQ Questions for Class 9 Science with Answers were prepared based on the latest exam pattern. These solutions will be useful for CBSE board exams, Science Olympiads, and other competitive exams. If that is the case, then you are in the right place. Practice the MCQs on 8th Class Science on a regular basis to get a good grip on the subject. Motion Class 9 Extra Questions and Answers Science Chapter 8 In this page, we are providing Motion Class 9 Extra Questions and Answers Science Chapter 8 pdf download. The speed v/s time graphs for the two cars can be plotted as follows. Those students who refer the NCERT Solutions regularly are benefited with the comprehensive methodology of the topic, and also with the detailed step by step procedure, which will fetch them good marks in their examinations. Statement (a) is false because the displacement of an object which travels a certain distance and comes back to its initial position is zero. If you have any query regarding NCERT Solutions for Class 9 Science Chapter 8 Motion , drop a comment below and we will get back to you at the earliest. In Text Question. If the initial position of the farmer is at the mid-point between two adjacent corners of the square, the net displacement of the farmer would be equal to the side of the square, which is 10m. MCQs from CBSE Class 9 Science Chapter 8: Motion 1. We already provided class 9 science NCERT solutions.CBSE Classs 9 Science Extra questions are very helpful to score more marks, devlop problem solving skill and excel in exams. 3. If the acceleration of the stone during its motion is 10 m s–2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? Therefore, the shaded area can be represented as: Area under the velocity-time graph = velocity*time. Class IX Science Solutions NCERT ... NCERT Solutions for Class 9 Science Chapter 8 : Motion – All Questions. If the displacement of an object is proportional to square of time, then the […] The total displacement of each car can be obtained by calculating the area beneath the speed-time graph. Distance covered in 40 seconds = 200π meters, Distance covered in 2minutes and 20 seconds (140 seconds) = 140 * 200π/40 meters, = (140*200*22)/(40* 7) meters = 2200 meters, Number of laps completed by the athlete in 140 seconds = 140/40 = 3.5. 2. Answer: Reproduction is the biological process by which new individual organisms are produced from their parents. For any error, please give your feedback, so that we can modify the contents. 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